Which term of the AP 3,15,27,3.... will be 120 more than its 21st term?
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a=3
d=15-3=12
an=120+a21
an=120+[3+(21-1)*12]
an=120+243=363
an=a+(n-1)d
363=3+(n-1)12
363-3/12=n-1
30+1=n
n=31
req. term= 31
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