which term of the AP 3,15,27,39 is 120 more then 21
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Given AP :- 3, 15, 27, 39, ..........
Here, a = 3.
d = 15-3 = 12.
First. we will obtain the 21st term.
By using formula, an = a + (n -1)d
a21 = 3 + (21 -1)12
= 3 + 20 × 12
= 3 + 240
= 243.
Hence, the 21st term of the AP is 243.
Now, term that is 120 more than 21st term will be
--> a21 + 120
--> 243 + 120
--> 363.
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