Question

Which term of the AP 3,15,27,39........Will be 132 more than 54th term. ​

Answer 1

Answer:

let the first term be "a" which is 3 and the common difference be "d" which is 12 in the given question

let us assume it's nth term be 132 more than it's 54th term

therefore,54th term (a54)

a54=a+53d

a54=3+53(12)

a54=3+636

a54=639

now,

an = a54 + 132

a+(n-1)d =639 + 132

3+(n-1) 12 = 771

(n-1) 12 = 771-3

(n-1) 12 = 768

(n-1) = 768/12

(n-1) = 64

n = 64+1

n=65

therefore 64th term of the AP 3,15,27,39........Will be 132 more than 54th term

Answer 2

Answer:48

Step-by-step explanation: 3+15+27+39=84

132-84=48