Question

which term of the AP 3 15 27 39 will be 132 more than 54th term

Answer 1

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Answer 2

A.P. => 3, 15, 27, 39
a = 3
d = 15 - 3 = 12
54th term of the A.P.
= a + (n - 1) d
= 3 + (54 - 1) 12
= 3 + 53 × 12
= 3 + 636
= 639
132 more than the 639 will be
= 639 + 132 = 771
$a_{n} = a + (n - 1)d \\ a_{n} = 771 \\ 771 = 3 + (n - 1)12 \\ 771 = 3 + 12n - 12 \\ 771 = - 9 + 12n \\ 771 + 9 = 12n \\ 12n = 780 \\ n = \frac{780}{12} = 65$
Hence, 65th term of the A.P. will be 132 more than its 54th term.

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