Question

which term of the AP 3,15,27,39,... Will be 132 more than it's 54th term

Answer 1

ap is 3,15.27....
a= 3
d=12
so find 54th term 
a+53d
3 +636
639 nd in this you can add 132
so it is 771 
in next step 
771 = a+(n-1)d
771= 3+12n -12
771= -9+12n
780 = 12n
n=65 
o the term is 65th term

Answer 2

☺ Hello mate__ ❤

◾◾here is your answer...

Lets first calculate 54th of the given AP.

First term = a = 3

Common difference = d =15 - 3 = 12

Using formula an=a+(n−1)d,  to find nth term of arithmetic progression, we get

a54=a+(54−1)d

a54=3+53(12)=3+636=639

We want to find which term is 132 more than its 54th term. Lets suppose it is nth term which is 132 more than 54th term.

Therefore, we can say that

an=a54+132 

......{an=a+(n−1)d=3+(n−1)(12)}{a54=639}

⇒3+(n−1)12=639+132

⇒3+12n−12=771

⇒12n−9=771

⇒12n=780

⇒n=780/12=65

Therefore, 65th term is 132 more than its 54th term.

I hope, this will help you.

Thank you______❤

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