which term of the AP 3,15,27,39,....will be 132 more than its 54th term?
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Answer:
65th term of the given AP will be 132 more than its 54th term.
Step-by-step explanation:
d= 15-3
=12
a=3
a54 = a+(54-1)d
=3+53 ×12
=3+636
=639
now, terms more than 54th term
an = 639+132
=771
a+(n-1)d = 771
3+(n-1) 12= 771
(n-1)12 = 768
n-1 = 768/12
=64
n = 64+1
n=65.
HOPE IT WILL YOU DEAR...
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