Question

Which term of the ap 3,15,27,39,...... will be 132 more than its 54th term

Answer 1

Answer:

$ap = 3 + 15 + 27 + 39....... \\ 132 \: more \: than \: its \: 54th \: terms \\ a = 3 \\ d = 12 \\ t54 = a + 53d \\ 3 + 53 \times 12 \\ 3 + 636 \\ 639 \\ = 132 + 639 \\ 771 \\ an = a + (n - 1)d \\ 771 = 3 + (n - 1)12 \\ 771 = 3 + 12n - 12 \\ 771 = 12n - 9 \\ 771 + 9 = 12n \\ 780 = 12n \\ n = 65$

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