Question

. Which term of the AP:3, 15, 27, 39,
will be 132 more than its 54th term ?​

Answer 1

Step-by-step explanation:

Given a = 3, d = 12, n = 54.

We know that an=a+(n-1) * d   ---------- (1)

                           = 3 + (54-1) * 12

                           = 3 + 53 * 12

                           = 639.

 a54 = 639.

Given that the term is 132 more than its 54th term = 639 + 132 = 771.

on substituting in (1), we get

771 = 3 + (n-1) * 12

768 = (n-1) * 12

768/12 = n-1

n-1 = 64

n = 65.

Therefore the 65th term is 132 more than its 54th term.

Hope this helps!