Question

Which term of the AP:3, 15, 27, 39, ... will be
132 more than its 54th term?​

Answer 1

Answer:

65

Step-by-step explanation:

hope you understand if you do please mark as brilliant

Answer 2

Answer:

The Desired Term is 65th Term.

Step-by-step explanation:

The Arithmetic Progression: 3, 15, 27, 39 . . . . . . . . .

= [3+(12 . 0)],  [3+(12 . 1)], [3+(12 . 2)], [3+(12 . 3)], . . . . . .

Its 54th term = [3+(12 . 53)], = 639

Value of the Desired Term = 639 + 132 = 771 = [3 + 768] = [3 + 12 . 64]

Therefore, the Desired Term is 65th Term.