Which term of the AP:3, 15, 27, 39, ... will be 132 more than its 54th term?
Answers
Answered by
1
Answer:
65th term is the required answer
Answered by
1
Answer:
65
Step-by-step explanation:
a= 3
d = 15-3 = 12
an = a+(n-1)d
We have to find the term which is 132 more than 54th term
a + (n-1)d = 132 +a + (54-1)d
3 + (n-1)12 = 132 + 3 + 53 × 12
(54-n) 12 =132
54 - n = 11
n = 65
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