Question

which term of the AP: 3, 15, 27, 39, .... will be 132 more than its 54th term?
plz answer in steps.

Answer 1

a = 3
d = 12

54th term = a + 53d

a + 53d + 132
= a + 53d + 11d
= a + 64d
=> 65th term

Hope this helps... plsss make it the brainliest

Answer 2

We have :

AP : 3, 15, 27, 39, .....

Here, the common difference 'd' is 12

ATQ :-

=> nth term = 132 + 54th term

=> a + (n - 1)d = 132 + a + 53d

=> (n - 1)d = 132 + 53d

=> (n - 1) = 11 + 53 [Since, d = 12]

=> n = 65

Thus, 65th term is the answer for this particular problem.

Hope it'll help you.....