Question

Which term of the ap 3, 15, 27, 39,... Will be 132 more than its 54th term brainly?

Answer 1

hey mate

here is the solution....

given:

first term (a)=3

common difference (d)=12

thus,the 54th term=

tn=a+(n-1)d

t54=3+(54-1)12

t54=3+53*12

t54=3+636

t54=639

let the term be x which is 132 more than 639

hence,

tn=132+639

a+(n-1)d=771

3+(n-1)12=771

(n-1)12=768

n-1=64

n=65 (answer)

thus,65th term will be 132 more than 54th term