Which term of the ap 3, 15, 27, 39,... Will be 132 more than its 54th term brainly?
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hey mate
here is the solution....
given:
first term (a)=3
common difference (d)=12
thus,the 54th term=
tn=a+(n-1)d
t54=3+(54-1)12
t54=3+53*12
t54=3+636
t54=639
let the term be x which is 132 more than 639
hence,
tn=132+639
a+(n-1)d=771
3+(n-1)12=771
(n-1)12=768
n-1=64
n=65 (answer)
thus,65th term will be 132 more than 54th term
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