which term of the AP 3,15,27,39_ _ _will be 132 more then it's 54 term.
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a=3
d=15-3=12
54th term of this is
n=54
Using the formula
An=a+(n-1)d
putting the values
A(54)=3+(54-1)12
A(54)=3+53×12=3+636=639
So, 132+54th term=132+639=771
So, An=771
and n=?
using the same formula
An=a+(n-1)d
putting the values
771=3+(n-1)12
771-3=(n-1)12
768÷12=(n-1)
64=n-1
n=64+1=65
So,The 65th term of of this ap is 132 more than its 54th term
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d=15-3=12
54th term of this is
n=54
Using the formula
An=a+(n-1)d
putting the values
A(54)=3+(54-1)12
A(54)=3+53×12=3+636=639
So, 132+54th term=132+639=771
So, An=771
and n=?
using the same formula
An=a+(n-1)d
putting the values
771=3+(n-1)12
771-3=(n-1)12
768÷12=(n-1)
64=n-1
n=64+1=65
So,The 65th term of of this ap is 132 more than its 54th term
I HOPE THIS WILL HELP YOU MARK ME BRAINLIEST
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