which term of the AP 3,15,27.... will be 120 more than its 64th term
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a=3 d=15-3=12
tn=3+12n-12=12n-9
t64= 12*64-9=758
t64+120=758+120=878
tn=12n-9=878
12n=878+9
n=887/12=73.9=74 th term
tn=3+12n-12=12n-9
t64= 12*64-9=758
t64+120=758+120=878
tn=12n-9=878
12n=878+9
n=887/12=73.9=74 th term
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