which term of the AP 3, 5, 27, 39 .................will be 120 more than its 21st term .
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Is this an Ap?
If so apply an formula to find a21 add 120 and find n for obtained an
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Answer: Common difference of series = (n+1) – n
we get 15-3,27-15....
common diffrence = 12
first term of series = 3
therefore 21 term of the series
is
T21 = a+d(n-1)
T21=3+12(21-1)
T21=243
Requried term after adding
120=120+243=363
Let first value of the series = 3
common difference = 12
term is = 363
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