Question

which term of the ap 3, 7, 11, 15, ... is 103

Answer 1

Let 103 be the nth term.

$\sf n_{th} \: term = a + (n-1)d$

where, a is the first term while d is the common difference.

$\sf 103= 3 + (n-1)4$

$\sf \: 100 = 4n - 4$

$\sf \: 104 = 4n$

$\sf \: n = \dfrac{104}{4} = 26$

103 is the 26th term of above A.P.