Question

which term of the AP 3, 7, 11, 15,.... will be 20 more than it's 6th term?​

Answer 1

Given:

An A.P is given to us with the terms 3, 7, 11, 15,

To Find:

We need to find that which term of the A.P will be 20 more than its 6th term?

Step-by-step explanation:

• We have an A.P with the terms 3,7,11,15

• Thus we can write the first term of A.P is a=3

•  Common difference of A.P is d is the given by the

                $d=a_2-a_1=7-3=4$

• Now nth term of A.P is given by the

                 $a_n=a+(n-1)d$

• Now 6th term of the A.P can be calculated as the From comparing above equation

                     $a_6=a+5d$

• Put the values a=3,d=4 in above equation

            $a_6=3+5(4)=3+20=23$

• Now According to question

                   $a_n=a_6+20$

• Put the values we get

                  $a+(n-1)d=23+20\\3+(n-1)4=43\\(n-1)5=43-3\\(n-1)=\frac{40}{5} =8\\n=8+1=9$

Hence 9th term will be 20 more then 6th term.

Answer 2

Answer:

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Step-by-step explanation:

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