Question

which term of the AP: 3, 8, 13, 18, ... is 78​

Answer 1

Answer:

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Step-by-step explanation:

Given A.P : 3,8,13,18,....,78

First term (a) = 3

common difference (d)= a3−a2

= 8-3

= 5

Let nth term=78

⟹a+(n−1)d=78

⟹3+(n−1)×5=78

⟹(n−1)×5=78−3

⟹(n−1)×5=75

⟹n−1= 75 / 5

⟹n−1=15

⟹n=15+1

⟹n=16

Therefore,

16th term in given A.P is 78