which term of the ap:3,8,13,18....,is 78
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Answered by
4
HEYA HERE'S UR ANSWER......
a1=3,
a2=8,
d=a2-a1
d=8-3
=5
an=a+(n-1)d.
given,an=78,
78=3+(n-1)5
78-3=(n-1)5
75/5=(n-1)
15=n-1
16=n.
78 is 16th term of the AP.
Hope this helps you quickly
a1=3,
a2=8,
d=a2-a1
d=8-3
=5
an=a+(n-1)d.
given,an=78,
78=3+(n-1)5
78-3=(n-1)5
75/5=(n-1)
15=n-1
16=n.
78 is 16th term of the AP.
Hope this helps you quickly
Cinderella100:
Thank you for your appreciation
Answered by
2
we know
nth term= a1 +(n-1)d
here a1 =3;d=8-3=5
therefore,
nth term = a1 + (n-1)d
78 = 3+(n-1)5
78=3+5n-5
80÷5=n
so,n=16 (ans)
nth term= a1 +(n-1)d
here a1 =3;d=8-3=5
therefore,
nth term = a1 + (n-1)d
78 = 3+(n-1)5
78=3+5n-5
80÷5=n
so,n=16 (ans)
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