Question

which term of the AP 4,0,-4.....is -392? in simple step mathod​

Answer 1

Step-by-step explanation:

✦Given:-

➨Radius = 50 cm \:

➨In 20 seconds the stone makes 10 revolutions.

➨In 1 seconds the revolution = 10/20 = 1/2 Hz

➨N = 1/2 Hz

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✦To Find:-

➨The magnitude of acceleration of the stone.

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✦Solution:-

Now,

✪( Let us use π as 3.14)✪

➨Angular Velocity ( ω ) = 2πn

➨ω= 2 × 3.14 × 50

✪ω = 314✪

➨Radial Acceleration = ω²r

➨Radial Acceleration = (3.14)² × 50 cm/s

➨Radial Acceleration = 492.98 cm/s = 493 cm/s

Hence, the magnitude of acceleration of the stone is 493 cm/s

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