Which term of the Ap 4,9,14,19.....is 124 (1) 3,6,9,12.....111
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Answer:
i} 25.
ii} 37
Step-by-step explanation:
i} an=a+{n-1}d
where a =4 and d=a2-a1=9-4=5
n=?
an=124
124=4+{n-1}5
124-4={n-1}5
120/5=n-1
24+1=n
25=n
ii} a=3, d=3, n=?, an=111
111=3+{n-1}3
111-3={n-1}3
108/3=n-1
36+1=n
37=n
Hope this will help you.
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