Question

which term of the AP 5,15,25,..... exceeds its 31st term by 130?

Answer 1

a=5

d=15-5

=10

a+(31-1)d=31st term

=a+30d

let x exceed it by 130.

x=a+30d+130

x=5+300+130

=435

x=a+(n-1)d

435=5+(n-1)10

10(n-1)=430

n-1=43

=n=44

Your answer 44th term.

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Answer 2

Answer:

Step-by-step explanation:

Please see the attachment below.

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