Which term of the AP:5,15,25...... will be 130 more than its 31th term?
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5
a = 5 .
d = 15 - 5 = 10
31 st term = 5 + ( 31 - 1 ) 10
= 5 + 30(10)
= 305 .
Now the term 130 more than 31st term = 305+130 = 435 .
Let 435 be the n th term of A. P
435 = 5 + ( n - 1 ) 10
435 = 5 + 10n - 10
435 = 10n - 5
440 = 10n
n = 44 .
44th term of A. P would be 130 more than its 31 st term
d = 15 - 5 = 10
31 st term = 5 + ( 31 - 1 ) 10
= 5 + 30(10)
= 305 .
Now the term 130 more than 31st term = 305+130 = 435 .
Let 435 be the n th term of A. P
435 = 5 + ( n - 1 ) 10
435 = 5 + 10n - 10
435 = 10n - 5
440 = 10n
n = 44 .
44th term of A. P would be 130 more than its 31 st term
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2
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