Which term of the AP 5,15,25, will be 130 mpre than its 31st term
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let 130 be the nth term of the ap
a=5
d=15-5
=-10
Now,
an=a+(n-1)d
130=5+(n-1)-10
130=5-10n+10
120-5=-10n
115/10=-n
-1.15=n
n=-1.15
but n should be a positive integer .
so,its not a term of the AP.
a=5
d=15-5
=-10
Now,
an=a+(n-1)d
130=5+(n-1)-10
130=5-10n+10
120-5=-10n
115/10=-n
-1.15=n
n=-1.15
but n should be a positive integer .
so,its not a term of the AP.
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