Which term of the AP 5, 8, 11,... will be 57 more than its 25th term?
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Step-by-step explanation:
let n term be 57 more than its 25 term
so,
a+(n-1)d= a+(25-1)d+57
5+(n-1)3= 5+(25-1)3+57
5+(n-1)3= 62+24×3
5+(n-1)3= 62+72
5+(n-1)3= 134
(n-1)3= 129
n-1= 43
n = 44
hence the term be 44
#666
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