Question

Which term of the AP 7,10,13,....is 160?

Answer 1

hope u understand my writing.

Answer 2

Therefore, 160 is 52nd term of given AP

Given:

7, 10, 13,....is Arithmetic sequence

To find:

Which term of the AP 7, 10, 13,....is 160

Solution:

Given AP 7, 10, 13,....is Arithmetic sequence

Here, first term a = 7

Common difference = term 2 - term 1 = 10 -7 = 3

In given series first term a = 7 and common difference d = 3

Let nth term of AP = 160

As we know nth term of AP, a$_{n}$ = a+(n-1)d

⇒ a+(n-1)d = 160

⇒ 7+(n-1)3 = 160

⇒ 3n - 3 = 153

⇒ 3n = 156

⇒ n = 156/3 = 52

Therefore, 160 is 52nd term of given AP

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