Question

Which term of the AP will be 132 more than its 54th term​

Answer 1

3+(54-1)×12

3+53×12

3+636

636

so,54th term =639

should be 639+132=771

therefor an =771

an =a +(n-1)d

771=3+(n-1)×12

771-3(n-1)×12

768=(n-1)×12

769\12=n-1

64=n-1

n-1=64

n=64+1

n=65