Question

which term of the aps 14,20,26... will be 72 more than the 41st term​

Answer 1

Answer:

AP :8,14,20,26...

a=8

d=14−8=6

Let T

n

=T

41

+72

a+(n−1)d=a+40d+72

⇒a+(n−1)d−a−40d=72

⇒d(n−1−40)=72

⇒6(n−41)=72

⇒n−41=12

⇒n=12+41

∴n=53

Required term = 53