Question

which term of the arithemitic progression 4, 9, 14 _ is 249?​

Answer 1

Answer:

the term is 50th

Step-by-step explanation:

nth term = a + (n-1)d

249 = 4 + (n-1)5

(249-4)/5= n-1

245/5 = n-1

49 = n-1

n = 50

Answer 2

Answer:

a = 4

d =5

a(n) = 249

n=?

a(n) = a+ (n-1)d

249 = 4+( n-1)5

245 = 5×(n-1)

n-1 = 49

n = 50

which is the required ans