Question

which term of the arithmetic progression 30 27 24 is zero​

Answer 1

Answer:

11th term.

Step-by-step explanation:

General term of AP = tn = a+(n-1)d

a = 30, d = 27-30=24-27=-3

ATQ. tn=0

=> tn=30+(n-1)-3

=> 0 = 30-3n+3

=> -33 = -3n

=> n = 33/3 = 11

Answer 2

Given:

A sequence that is in the form of an arithmetic progression 30 27 24.

To find:

The term of the given AP that is equal to zero.

Solution:

As we know that in an AP, the nth term can be found out by using the formula:

${n}^{th} \: term = a + (n - 1)d$

where a = first term, d = common difference and n = number of terms.

So, in the given AP 30 27 24, we have,

a = 30,

d = second term - first term = 27 - 30 = -3

nth term= zero

So, using the above formula, we find the term of the given AP which is equal to zero.

Thus,

$30 + (n - 1) (- 3) = 0$

$30 - 3n + 3 = 0$

$- 3n + 33 = 0$

$3n = 33$

$n = \frac{33}{3} = 11$

Hence, the term of the given arithmetic progression 30 27 24 which is equal to zero is eleventh.