Question

Which term of the Arithmetic progression 5, 15, 25,....... will be 130 more than its 31st term?​

Answer 1

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Answer 2

44 th Term

Given:

First term of the Arithmetic Progression = 5

Calculating the common Difference of the Arthimetic Progression:

=  a2 - a1

= 15 - 5

= 10

The 31 st term of the Arithmetic Progression:

= a + 30d

Adding 130 to the 31 st term:

= a + 30d + 130

Substituting the values known to us in this equation we get:

= 5 + 30 x 10 + 130

= 5 + 300 + 130

= 435

To find the nth term of the AP we use the formula:

an = a + (n - 1) d

435 = 5 + (n - 1) 10

430 = (n - 1) 10

430 / 10 = n - 1

43 = n -1

n = 43 + 1

n = 44

Therefore 44 is the term that would be 130 more than the 31 st term of the Arithmetic Progression.