. Which term of the arithmetic progression 5, 9, 13,.... will be 88 more than its 37th term?
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Answered by
7
a = 5
d = 4
Tn = T37 + 88
=> a + (n-1)d = a + 36d + 88
=> 5 + (n-1) (4) = 5 + 36(4) + 88
=> 5 + (n-1) (4) = 5 + 144 + 88
=> (n-1) (4) = 232
=> n - 1 = 58
=> n = 59
=> 59th term of the given AP is 88 more than 37th term
d = 4
Tn = T37 + 88
=> a + (n-1)d = a + 36d + 88
=> 5 + (n-1) (4) = 5 + 36(4) + 88
=> 5 + (n-1) (4) = 5 + 144 + 88
=> (n-1) (4) = 232
=> n - 1 = 58
=> n = 59
=> 59th term of the given AP is 88 more than 37th term
Answered by
1
a = 5
d = 4
Tn = T37 + 88
=> a + (n-1)d = a + 36d + 88
=> 5 + (n-1) (4) = 5 + 36(4) + 88
=> 5 + (n-1) (4) = 5 + 144 + 88
=> (n-1) (4) = 232
=> n - 1 = 58
=> n = 59
=> 59th term of the given AP is 88 more than 37th term
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