Question

. Which term of the arithmetic progression 5, 9, 13,.... will be 88 more than its 37th term?

Answer 1

a = 5

d = 4

Tn = T37 + 88

=> a + (n-1)d = a + 36d + 88

=> 5 + (n-1) (4) = 5 + 36(4) + 88

=> 5 + (n-1) (4) = 5 + 144 + 88

=> (n-1) (4) = 232

=> n - 1 = 58

=> n = 59

=> 59th term of the given AP is 88 more than 37th term

Answer 2

a = 5

d = 4

Tn = T37 + 88

=> a + (n-1)d = a + 36d + 88

=> 5 + (n-1) (4) = 5 + 36(4) + 88

=> 5 + (n-1) (4) = 5 + 144 + 88

=> (n-1) (4) = 232

=> n - 1 = 58

=> n = 59

=> 59th term of the given AP is 88 more than 37th term