Question

Which term of the G.P : 2,2 √2, 4,... is 128 ?​

Answer 1

Answer:

We have,

G.P.=2,2

2

,4.........is128

First term a=2

Common ration r=

2

2

2

=

2

Number of terms n=?

Last term l=128

Then ,

We know that,

l=ar

n−1

128=2(

2

)

n−1

(

2

)

n−1

=

2

128

(

2

)

n−1

=64

(

2

)

n−1

=2

6

(

2

)

n−1

=(

2

)

12

n−1=12

n=12+1

n=13

Hence, this is the answer

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