which term of the given series would be the first one to be a four digit number:192 288 432 648.....?
Answers
Answered by
1
Given Series is 192, 288, 432, 648.
Now,
First-term a1 = 192.
Common ratio r = 288/192
= 3/2.
We know that an = a1. r^(n - 1).
= > an = 192. (3/2)^(n - 1)
Now,
5th term = 192(3/2)^(5 - 1)
= 192(3/2)^4
= 192(81/16)
= 972.
6th term = 192(3/2)^(6 - 1)
= 192(3/2)^5
= 192(243/32)
= 1458.
The series is 192,288,432,648,972,1458....
Therefore 6th term will be the first one to be a four-digit number.
Hope this helps!
Now,
First-term a1 = 192.
Common ratio r = 288/192
= 3/2.
We know that an = a1. r^(n - 1).
= > an = 192. (3/2)^(n - 1)
Now,
5th term = 192(3/2)^(5 - 1)
= 192(3/2)^4
= 192(81/16)
= 972.
6th term = 192(3/2)^(6 - 1)
= 192(3/2)^5
= 192(243/32)
= 1458.
The series is 192,288,432,648,972,1458....
Therefore 6th term will be the first one to be a four-digit number.
Hope this helps!
siddhartharao77:
:-)
Similar questions