Question

Which term of the gp is 1/3,1/2,3/4 is 243/64

Answer 1

Answer:

G. P

a = 1/3

r = (1/2)/(1/3) = (3/2)

an = a*r^(n-1)

243/64 = (1/3)*(3/2)^(n-1)

(243*3) /64 = (3/2) ^(n-1)

(729/64) = (3/2) ^(n-1)

(3/2)^6 = (3/2)^(n-1)

as bases are equal, we can compare the exponents

(n-1) = 6

n= 6+1 = 7

(243/64) is 7 th term of G.P....

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