Question

Which term of the progression 19, 18⅕, 17⅖,….is the first negative term.​

Answer 1

Answer:

Here a=19 , d= \(18\frac{1}{5}-\9\)=\(frac){4}{5}\)

Step-by-step explanation:

Let the nth term be the first negative. The

Tn <0>=a+(n-1)*d<0

=19+(n-1){-4/5}<0

19-\

(frac{4}{5}\)n+\(\frac{4}{5}\<0

=\(\frac{99}{5}\)-\(\frac{4}{5}

n>\(\frac{99}{5}*\(\frac{4}{5}\)n<0

n>\(\frac{99}{4}\)=\(24\frac{3}{4}

n=25