which term of the sequence 18,12,8........... is 512÷729?
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6 is the sequence of term
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hope it helps you
Swarup1998:
the term is the 9th
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19
The answer is given below :
The given sequence is
18, 12, 8, ...
It is a Geometric Progression.
First term (a) = 18
Common difference (r) = 12/18 = 2/3
Let us consider that 512/729 be the n-th term of the sequence.
Then, a × r^(n - 1) = 512/729
⇒ 18 × (2^3)^(n - 1) = 512/729
⇒ 18 × (2/3)^n × (2/3)^(-1) = 512/729,
since x^(a + b) = x^a × x^b
⇒ 18 × 3/2 × (2/3)^n = 512/729,
since (2/3)^(-1) = 1/(2/3) = 3/2
⇒ 27 × (2/3)^n = 512/729
⇒ (2/3)^n = 512/729 × 1/27
⇒ (2/3)^n = 512/19683
⇒ (2/3)^n = (2/3)^9
Comparing the powers, we get n = 9
Therefore, the 9th term of the given sequence is 512/729.
Thank you for your question.
The given sequence is
18, 12, 8, ...
It is a Geometric Progression.
First term (a) = 18
Common difference (r) = 12/18 = 2/3
Let us consider that 512/729 be the n-th term of the sequence.
Then, a × r^(n - 1) = 512/729
⇒ 18 × (2^3)^(n - 1) = 512/729
⇒ 18 × (2/3)^n × (2/3)^(-1) = 512/729,
since x^(a + b) = x^a × x^b
⇒ 18 × 3/2 × (2/3)^n = 512/729,
since (2/3)^(-1) = 1/(2/3) = 3/2
⇒ 27 × (2/3)^n = 512/729
⇒ (2/3)^n = 512/729 × 1/27
⇒ (2/3)^n = 512/19683
⇒ (2/3)^n = (2/3)^9
Comparing the powers, we get n = 9
Therefore, the 9th term of the given sequence is 512/729.
Thank you for your question.
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