Which term of the sequence {3,19,35,…} is 307 pls answer asap and have a solution pls
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Answer:
20th
Step-by-step explanation:
Here,
First term(a)=3
Common difference (d)=16
T(n)=a+(n-1)d
=>307=3+(n-1)16
=>(n-1)16=307-3=304
=>n-1=304/16=19
=>n=19+1=20
Hence 20th term of the given A.P. is 307.
Hope it helped u
Thanks
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