Math, asked by rafaelaacabal21, 7 months ago

Which term of the sequence {3,19,35,…} is 307 pls answer asap and have a solution pls

Answers

Answered by Anonymous
0

Answer:

20th

Step-by-step explanation:

Here,

First term(a)=3

Common difference (d)=16

T(n)=a+(n-1)d

=>307=3+(n-1)16

=>(n-1)16=307-3=304

=>n-1=304/16=19

=>n=19+1=20

Hence 20th term of the given A.P. is 307.

Hope it helped u

Thanks

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