Math, asked by khalkoalbert1, 17 days ago

Which term of the sequence 3. 6. 9, 12, (Ch-5 Arithmetic Progression) is 489?

Answers

Answered by anonymous1739

1

Answer:

163

Step-by-step explanation:

tn = a+(n-1)d

tn = 3+(n-1)*3

tn = 3n

489 = 3n

n= 489/

n= 163

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