which term of the sequence 36 31 26 21 16 is the first negative term
Answers
Answered by
3
The first negative term is 9th term
Step-by-step explanation:
AP 36,31,26,21
First term = a = 36
Common difference = d = 31-36=26-31 = -5
Formula of nth term =
We are supposed to find first negative term
So, The first negative term must be 9th term
Hence The first negative term is 9th term
Answered by
0
Answer:
9th term.
Step-by-step explanation:
Let the unknown term be an
GIven that =
an < 0
a + {n-1}d < 0
where
a = 36
d = 31-36 = -5
So,
36 + {n-1} x -5 < 0
n-1 < -36/-5
n-1 < 7.2
n < 8.2
n = approx 9
Verification
a9 = a + 8d
= 36 + 8 x -5
= 36 - 40
= -4
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