Which term of the sequence 4,9,14,19 ......is 104
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Answer:
given
a=4 d=9-4=5 an=104
n=?
an=a+(n-1)d
104=4+(n-1)5
104-4=(n-1)5
100=5n-5
100+5=5n
105=5n
105/5=n
21=n
therefore,21st term is 104
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