Which term of the sequence 73, 69, 65, 61,
is -23
A 24
B 23
c 25
D 26
Answers
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3
Answer:
option c ,25
Step-by-step explanation:
it is a arithemitic progression where the common difference is of -4 , which will be constant throught the series ...
now let nth term be -23 ,
and apply the formula an = a1 +(n-1)d
now substitute the value , you have a1=73 , an=-23 and d=-4
so -23=73 -(n-1)4
=> -96= -(n-1)4
=> 24=n-1
=> n=25
hope it helped you,thank the answer please
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