Question

Which term of the series 16,14,12....are 0 and -16?

Answer 1

your answer is here

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Answer 2

Answer:

(1) 9. (2) 17

Step-by-step explanation:

(1)here t=0

a+(n-1)d=t

16+(n-1)-2=0

16 - 2n+2=0

18- 2n =0

18=2n

n=9

(2)

here t=-16

again

a+(n-1)d=-16

16+(n-1)-2=-16

16-2n+2=-16

18 -2n =-16

34=2n

n=17