Question

Which term of the series 16,8,4,2.....is 1/6

Answer 1

Answer:

G.P

a=16

r=a2/a1=8/16=1/2

an=a(r^(n-1))

1/6=16(1/2)^(n-1)

1/96=(1/2)^(n-1)

2^(n-1)=96

applying log on both sides

(n-1) log 2 = log 96

n-1= log 96/log 2

n = log 96 base 2 + 1

n is not an integer.

so, 1/6 is not the term of the series.

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