which term of the series -3,-1,5,..is 53
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Answer:
-3,-1,5
a = -3
d = t²-t¹ = -1-(-3) = -1+3 = 2
t³-t² = 5+1 = 6
d = 6-2 = 4
tn = a+(n-1)d
53 = -3 +(n-1)4
53+3 = n-1 * 4
56/4 = n-1
14 = (n-1)
n = 14+1 = 15
Therefore,15th term of series is 53
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