Question

which term of the series 3+8+13+18+......... is 498

a. 95th
b. 100th
c. 102th
d. 101th


plz give the answer with method

Answer 1

Answer:

Option(b)

Step-by-step explanation:

Clearly the given Series is in A.P.

Here,

First term a = 3

Common Difference d = 5

Last term an = 498

Now,

an = a + (n - 1) * d

⇒ 498 = 3 + (n - 1) * 5

⇒ 498 = 3 + 5n - 5

⇒ 498 = 5n - 2

⇒ 500 = 5n

⇒ n = 100

So, the 100th term of the A.P is 78.

Hope it helps!

Answer 2

nth term=a+(n-1)d

=>498=3+(n-1)5

=>498=3+5n-5

=>498+2=5n

=>n=500/5=100th term

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