Question

which term of the series 4+9+14+.........is 254 ?

Answer 1

Number series : 4 + 9 + 14 ....

⇒ First term = a1 = 4

⇒ Common difference = 9 - 4 = 5

Form the equation:

an = a1 + (n - 1)d

an = 4 + 5(n - 1)

an = 4 + 5n - 5

an = 5n - 1

Find n where an = 254:

an = 5n - 1

254 = 5n - 1

5n = 255

n = 255 ÷ 5

n = 51

Answer: The 51st term is 254.

Answer 2

51th term of the series is 254

Step-by-step explanation:

Given series 4 + 9 + 14 + ... 254.

9 - 4 = 5

14 - 9 = 5

Difference are equal. Therefore it is AP.

a = 4, d = 5 and $a_n = 254$

Arithmetic formula:

$a_n=a+(n-1)d$

$254=4+(n-1)5$

$254=4+5n-5$

$254=5n-1$

$254+1=5n$

$255=5n$

Divide by 5, we get

51 = n

Switch the sides.

n = 51

Therefore 51th term of the series is 254.

To learn more...

1. Which term of this series 4+9+14+...is 254.

https://brainly.in/question/3337446

2. Determine the 10th term of the end of the AP 4, 9, 14,.. ., 254

https://brainly.in/question/3038960