Question

which term of the series 5, 8 ,11.... is 320

Answer 1

in this AP
a=5
d= 3
let the nth term be 320

then, a +(n-1)d = 320
=> 5+ (n-1) 3 = 320
=> 3n -3+5 = 320
=> 3n +2 = 320
=> 3n = 318
=> n = 318/3 = 106
Hence, the 106th term is 320