which term of the series 79,77,75... is 47
Answers
Answered by
1
a=79
d=-2
an=47
n=?
an=a+(n-1)d
47=79+(n-1)(-2)
(n-1)(-2)=-32
n-1=-32/-2
n-1=16
n=16+1
n=17
d=-2
an=47
n=?
an=a+(n-1)d
47=79+(n-1)(-2)
(n-1)(-2)=-32
n-1=-32/-2
n-1=16
n=16+1
n=17
Answered by
0
So the ans is 17th term.... an=a+(n-1)d 47=79+(n-1)-2 -32=-2n+2 -34=-2n 17=n
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