Which term of the series is 635 if the first term is 15 and the common difference is 5
Answers
Answered by
0
Given:
an=635
First term (a1)= 15
Common difference (d)=5
To Find:
n=?
Solution:
an=a+(n-1)d
635=15+(n-1)5
635=15+5n-5
635=10+5n
635-10=5n
625=5n
5n=625
n=625/5
n=125
Similar questions